CHAPTER 11.1. Given the vectors M =−10ax +4ay −8az and N = 8ax +7ay −2az, find: a) a unit vector in the direction of−M+2N. −M+2N = 10ax −4ay +8az +16ax +14ay −4az = (26,10,4) Thus a = (26,10,4) |(26,10,4)| = (0.92,0.36,0.14) b) the magnitude of 5ax +N−3M: (5,0,0)+(8,7,−2)−(−30,12,−24) = (43,−5,22), a[r]