Pđt = P2 + pCu2 = 3200.103 + 12,98.103 = 3212,98.103 (W)Qđt = Q2 + q2 = 2400.103 + 108,86.103 = 2508,86.103 (VAR)pcu
1 = 3.R1.I1f2 = 3 .0,4.(104,97)2 =13,2.103(W)q1= 3.X1.I1f2 = 3 .3,3.(104,97)2 = 109,08.103(VAR)pFe = 3.Rth.Iof2 =3. 1,096.103 . (1,15 )2 = 4,34.103 (W)qFe= 3.Xth. Iof2 = 3. 10,9[r]