ELECTRIC MACHINERY

δδ 179= −=P At °= 45δ, 179 kW can be drawn from the motor. 301 Appendix D: Errata for Electric Machinery Fundamentals 4/e (Current at 10 January 2004) Please note that some or all of the following errata may be corrected in future reprints of the book, so they may not appe[r]

Assume that the field current of the generator in Problem 5-2 is adjusted to achieve rated voltage 2300 V at full load conditions in each of the questions below.. _a What is the efficien[r]

πω== = ⋅ Note that the induced torque is proportional to the square of the terminal voltage. 10-7. What type of motor would you select to perform each of the following jobs? Why? (a) Vacuum cleaner (b) Refrigerator (c) Air conditioner compressor (d) Air conditioner fan (e) Variable-speed sewi[r]

IF THE MACHINE IN PROBLEM 9-25 IS RUNNING AT 1800 R/MIN WITH A FIELD RESISTANCE _R_adj = 10 Ω and an armature current of 25 A, what will the resulting terminal voltage be?. If the field [r]

[Note: Assume that 1 the brush voltage drop is 2 V; 2 the core loss is to be determined at an armature voltage equal to the armature voltage under full load; and 3 stray load losses are [r]

A 480-V 100-kW 0.85-PF leading 50-Hz six-pole Y-connected synchronous motor has a synchronous reactance of 1.5 Ω and a negligible armature resistance.. The rotational losses are also to [r]

The motor speed in radians per second is 2 rad 1 min 3420 r/min 358 rad/s 1 r 60 s _m_ π ω = = TRANG 6 SOLUTION The slip at pullout torque is found by calculating the Thevenin equivale[r]

96 % Plot a closeup of the near spectrum % (positive side only) figure(5); plot(fftshift(fstep),fftshift(abs(spec))); title('\bfSpectrum of Output Voltage for fr = 500 Hz'); xlabel('\bfFrequency (Hz)'); ylabel('\bfAmplitude'); set(gca,'Xlim',[0 1000]); When this program is executed, the input, ref[r]

SOLUTION At the beginning of each half cycle, the voltages across the DIAC and the SCR will both be smaller then their respective breakover voltages, so no current will flow to the load [r]

In the short-circuit test, the recorded values on the high-voltage side for one of these transformers are _V_ SC = 560 V _I_SC =12.6A _P_SC =3300W _a If this bank delivers a rated load a[r]

The resulting plot is _b_ When this transformer is connected to a 240-V 50 Hz source, the flux in the core will be given by the equation cos _t_ _N_ _V_ _t_ _S_ _M_ Ω Ω Φ =− The magnet[r]